0007: Reverse Integer
Problem Statement
Given a signed 32-bit integer x
, return x
with its digits reversed. If reversing x
causes the value to go outside the signed 32-bit integer range [-231, 231 - 1]
, then return 0
.
Assume the environment does not allow you to store 64-bit integers (signed or unsigned).
Example 1:
Input: x = 123 Output: 321
Example 2:
Input: x = -123 Output: -321
Example 3:
Input: x = 120 Output: 21
Constraints:
-231 <= x <= 231 - 1
Code Solution
class Solution:
def reverse(self, x: int) -> int:
# record the sign
sign = -1 if x < 0 else +1
# set limits without overflowing the values
limit = 2 ** 30 + ((2 ** 30) - 1) if sign == +1 else 2 ** 31
x = abs(x)
cnum = 0
while x:
# look ahead if overflow can happen
if cnum > limit // 10:
return 0
# corner case for overflow comparing last digit
if cnum == limit // 10 and (x % 10 > limit % 10):
return 0
# update the value:
cnum = cnum * 10 + (x % 10)
x = x // 10
return sign * cnum